1111132111231 has 2 divisors, whose sum is σ = 1111132111232. Its totient is φ = 1111132111230.

The previous prime is 1111132111153. The next prime is 1111132111267. The reversal of 1111132111231 is 1321112311111.

It is a m-pointer prime, because the next prime (1111132111267) can be obtained adding 1111132111231 to its product of digits (36).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1111132111231 - 2¹¹ = 1111132109183 is a prime.

It is a super-2 number, since 2×1111132111231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111132111199 and 1111132111208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111132411231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555566055615 + 555566055616.

It is an arithmetic number, because the mean of its divisors is an integer number (555566055616).

Almost surely, 2^{1111132111231} is an apocalyptic number.

1111132111231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111132111231 is an equidigital number, since it uses as much as digits as its factorization.

1111132111231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36, while the sum is 19.

Adding to 1111132111231 its reverse (1321112311111), we get a palindrome (2432244422342).

It can be divided in two parts, 1111 and 132111231, that multiplied together give a palindrome (146775577641).

The spelling of 1111132111231 in words is "one trillion, one hundred eleven billion, one hundred thirty-two million, one hundred eleven thousand, two hundred thirty-one".