1111133100331 has 4 divisors (see below), whose sum is σ = 1159443235152. Its totient is φ = 1062822965512.

The previous prime is 1111133100299. The next prime is 1111133100359. The reversal of 1111133100331 is 1330013311111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1111133100331 - 2⁵ = 1111133100299 is a prime.

It is a super-2 number, since 2×1111133100331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1111133100299 and 1111133100308.

It is not an unprimeable number, because it can be changed into a prime (1111133140331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24155067376 + ... + 24155067421.

It is an arithmetic number, because the mean of its divisors is an integer number (289860808788).

Almost surely, 2^{1111133100331} is an apocalyptic number.

1111133100331 is a deficient number, since it is larger than the sum of its proper divisors (48310134821).

1111133100331 is an equidigital number, since it uses as much as digits as its factorization.

1111133100331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48310134820.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1111133100331 its reverse (1330013311111), we get a palindrome (2441146411442).

The spelling of 1111133100331 in words is "one trillion, one hundred eleven billion, one hundred thirty-three million, one hundred thousand, three hundred thirty-one".