1111140433 has 4 divisors (see below), whose sum is σ = 1196612788. Its totient is φ = 1025668080.

The previous prime is 1111140403. The next prime is 1111140439. The reversal of 1111140433 is 3340411111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 131951169 + 979189264 = 11487^2 + 31292^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111140433 - 2²⁵ = 1077586001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1111140433.

It is not an unprimeable number, because it can be changed into a prime (1111140439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42736158 + ... + 42736183.

It is an arithmetic number, because the mean of its divisors is an integer number (299153197).

Almost surely, 2^1111140433 is an apocalyptic number.

1111140433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1111140433 is a deficient number, since it is larger than the sum of its proper divisors (85472355).

1111140433 is an equidigital number, since it uses as much as digits as its factorization.

1111140433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85472354.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1111140433 is about 33333.7731587650. The cubic root of 1111140433 is about 1035.7532795638.

Adding to 1111140433 its reverse (3340411111), we get a palindrome (4451551544).

The spelling of 1111140433 in words is "one billion, one hundred eleven million, one hundred forty thousand, four hundred thirty-three".