11112100020041 has 2 divisors, whose sum is σ = 11112100020042. Its totient is φ = 11112100020040.

The previous prime is 11112100020019. The next prime is 11112100020089. The reversal of 11112100020041 is 14002000121111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10167354899641 + 944745120400 = 3188629^2 + 971980^2 .

It is an emirp because it is prime and its reverse (14002000121111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11112100020041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11112100019998 and 11112100020025.

It is not a weakly prime, because it can be changed into another prime (11112100023041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556050010020 + 5556050010021.

It is an arithmetic number, because the mean of its divisors is an integer number (5556050010021).

Almost surely, 2^{11112100020041} is an apocalyptic number.

It is an amenable number.

11112100020041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11112100020041 is an equidigital number, since it uses as much as digits as its factorization.

11112100020041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 11112100020041 its reverse (14002000121111), we get a palindrome (25114100141152).

The spelling of 11112100020041 in words is "eleven trillion, one hundred twelve billion, one hundred million, twenty thousand, forty-one".