111121003113 has 4 divisors (see below), whose sum is σ = 148161337488. Its totient is φ = 74080668740.

The previous prime is 111121003111. The next prime is 111121003127. The reversal of 111121003113 is 311300121111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111121003113 - 2¹ = 111121003111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111121003092 and 111121003101.

It is not an unprimeable number, because it can be changed into a prime (111121003111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18520167183 + ... + 18520167188.

It is an arithmetic number, because the mean of its divisors is an integer number (37040334372).

Almost surely, 2^111121003113 is an apocalyptic number.

It is an amenable number.

111121003113 is a deficient number, since it is larger than the sum of its proper divisors (37040334375).

111121003113 is an equidigital number, since it uses as much as digits as its factorization.

111121003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37040334374.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 111121003113 its reverse (311300121111), we get a palindrome (422421124224).

The spelling of 111121003113 in words is "one hundred eleven billion, one hundred twenty-one million, three thousand, one hundred thirteen".