1111210320113 has 2 divisors, whose sum is σ = 1111210320114. Its totient is φ = 1111210320112.

The previous prime is 1111210320097. The next prime is 1111210320131. The reversal of 1111210320113 is 3110230121111.

Together with next prime (1111210320131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 978154626289 + 133055693824 = 989017^2 + 364768^2 .

It is an emirp because it is prime and its reverse (3110230121111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111210320113 - 2⁴ = 1111210320097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111210320091 and 1111210320100.

It is not a weakly prime, because it can be changed into another prime (1111210320013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555605160056 + 555605160057.

It is an arithmetic number, because the mean of its divisors is an integer number (555605160057).

Almost surely, 2^{1111210320113} is an apocalyptic number.

It is an amenable number.

1111210320113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111210320113 is an equidigital number, since it uses as much as digits as its factorization.

1111210320113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1111210320113 its reverse (3110230121111), we get a palindrome (4221440441224).

The spelling of 1111210320113 in words is "one trillion, one hundred eleven billion, two hundred ten million, three hundred twenty thousand, one hundred thirteen".