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11112111531113 is a prime number
BaseRepresentation
bin1010000110110011110101…
…1101011110010001101001
31110100022022011021112211112
42201230331131132101221
52424030101022443423
635344500014440105
72224552324365215
oct241547535362151
943308264245745
1011112111531113
1135a46902a365a
1212b5727803035
13627b38218548
142a5b86d67945
151440b8d45a78
hexa1b3d75e469

11112111531113 has 2 divisors, whose sum is σ = 11112111531114. Its totient is φ = 11112111531112.

The previous prime is 11112111531067. The next prime is 11112111531203. The reversal of 11112111531113 is 31113511121111.

It is a m-pointer prime, because the next prime (11112111531203) can be obtained adding 11112111531113 to its product of digits (90).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10504003216144 + 608108314969 = 3240988^2 + 779813^2 .

It is a cyclic number.

It is not a de Polignac number, because 11112111531113 - 230 = 11111037789289 is a prime.

It is not a weakly prime, because it can be changed into another prime (11112111537113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556055765556 + 5556055765557.

It is an arithmetic number, because the mean of its divisors is an integer number (5556055765557).

Almost surely, 211112111531113 is an apocalyptic number.

It is an amenable number.

11112111531113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11112111531113 is an equidigital number, since it uses as much as digits as its factorization.

11112111531113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 90, while the sum is 23.

Adding to 11112111531113 its reverse (31113511121111), we get a palindrome (42225622652224).

The spelling of 11112111531113 in words is "eleven trillion, one hundred twelve billion, one hundred eleven million, five hundred thirty-one thousand, one hundred thirteen".