11112120433 has 4 divisors (see below), whose sum is σ = 11595256128. Its totient is φ = 10628984740.

The previous prime is 11112120421. The next prime is 11112120473. The reversal of 11112120433 is 33402121111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33402121111 = 137 ⋅243811103.

It is a cyclic number.

It is not a de Polignac number, because 11112120433 - 2⁵ = 11112120401 is a prime.

It is a super-2 number, since 2×11112120433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11112120433.

It is not an unprimeable number, because it can be changed into a prime (11112120403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241567813 + ... + 241567858.

It is an arithmetic number, because the mean of its divisors is an integer number (2898814032).

Almost surely, 2^11112120433 is an apocalyptic number.

It is an amenable number.

11112120433 is a deficient number, since it is larger than the sum of its proper divisors (483135695).

11112120433 is an equidigital number, since it uses as much as digits as its factorization.

11112120433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 483135694.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11112120433 its reverse (33402121111), we get a palindrome (44514241544).

The spelling of 11112120433 in words is "eleven billion, one hundred twelve million, one hundred twenty thousand, four hundred thirty-three".