1111212111133 has 2 divisors, whose sum is σ = 1111212111134. Its totient is φ = 1111212111132.

The previous prime is 1111212111077. The next prime is 1111212111169. The reversal of 1111212111133 is 3311112121111.

It is a m-pointer prime, because the next prime (1111212111169) can be obtained adding 1111212111133 to its product of digits (36).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 831120308964 + 280091802169 = 911658^2 + 529237^2 .

It is an emirp because it is prime and its reverse (3311112121111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111212111133 - 2³³ = 1102622176541 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1111212111133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111212111533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555606055566 + 555606055567.

It is an arithmetic number, because the mean of its divisors is an integer number (555606055567).

Almost surely, 2^{1111212111133} is an apocalyptic number.

It is an amenable number.

1111212111133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111212111133 is an equidigital number, since it uses as much as digits as its factorization.

1111212111133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36, while the sum is 19.

Adding to 1111212111133 its reverse (3311112121111), we get a palindrome (4422324232244).

It can be divided in two parts, 11112121111 and 33, that multiplied together give a palindrome (366699996663).

The spelling of 1111212111133 in words is "one trillion, one hundred eleven billion, two hundred twelve million, one hundred eleven thousand, one hundred thirty-three".