11112132121113 has 4 divisors (see below), whose sum is σ = 14816176161488. Its totient is φ = 7408088080740.

The previous prime is 11112132121061. The next prime is 11112132121121. The reversal of 11112132121113 is 31112123121111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11112132121113 - 2¹² = 11112132117017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11112132121113.

It is not an unprimeable number, because it can be changed into a prime (11112132121613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1852022020183 + ... + 1852022020188.

It is an arithmetic number, because the mean of its divisors is an integer number (3704044040372).

Almost surely, 2^{11112132121113} is an apocalyptic number.

It is an amenable number.

11112132121113 is a deficient number, since it is larger than the sum of its proper divisors (3704044040375).

11112132121113 is an equidigital number, since it uses as much as digits as its factorization.

11112132121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3704044040374.

The product of its digits is 72, while the sum is 21.

Adding to 11112132121113 its reverse (31112123121111), we get a palindrome (42224255242224).

The spelling of 11112132121113 in words is "eleven trillion, one hundred twelve billion, one hundred thirty-two million, one hundred twenty-one thousand, one hundred thirteen".