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111121323121117 is a prime number
BaseRepresentation
bin11001010001000001110010…
…111111011101100111011101
3112120110002120001211100001101
4121101001302333131213131
5104031102432204333432
61032200233041513101
732256151656010141
oct3121016277354735
9476402501740041
10111121323121117
1132452319a7a731
1210568082342791
134a009078c625a
141d6242d30d221
15cca7c218a4e7
hex651072fdd9dd

111121323121117 has 2 divisors, whose sum is σ = 111121323121118. Its totient is φ = 111121323121116.

The previous prime is 111121323121057. The next prime is 111121323121187. The reversal of 111121323121117 is 711121323121111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111116454710041 + 4868411076 = 10541179^2 + 69774^2 .

It is a cyclic number.

It is not a de Polignac number, because 111121323121117 - 223 = 111121314732509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111121323121187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560661560558 + 55560661560559.

It is an arithmetic number, because the mean of its divisors is an integer number (55560661560559).

Almost surely, 2111121323121117 is an apocalyptic number.

It is an amenable number.

111121323121117 is a deficient number, since it is larger than the sum of its proper divisors (1).

111121323121117 is an equidigital number, since it uses as much as digits as its factorization.

111121323121117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 504, while the sum is 28.

Adding to 111121323121117 its reverse (711121323121111), we get a palindrome (822242646242228).

The spelling of 111121323121117 in words is "one hundred eleven trillion, one hundred twenty-one billion, three hundred twenty-three million, one hundred twenty-one thousand, one hundred seventeen".