11112210041 has 4 divisors (see below), whose sum is σ = 11595349632. Its totient is φ = 10629070452.

The previous prime is 11112210019. The next prime is 11112210091. The reversal of 11112210041 is 14001221111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14001221111 = 12659 ⋅1106029.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11112210041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11112209998 and 11112210025.

It is not an unprimeable number, because it can be changed into a prime (11112210001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241569761 + ... + 241569806.

It is an arithmetic number, because the mean of its divisors is an integer number (2898837408).

Almost surely, 2^11112210041 is an apocalyptic number.

It is an amenable number.

11112210041 is a deficient number, since it is larger than the sum of its proper divisors (483139591).

11112210041 is an equidigital number, since it uses as much as digits as its factorization.

11112210041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 483139590.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 11112210041 its reverse (14001221111), we get a palindrome (25113431152).

The spelling of 11112210041 in words is "eleven billion, one hundred twelve million, two hundred ten thousand, forty-one".