Base | Representation |
---|---|
bin | 10100101100101011… |
… | …01110101010001011 |
3 | 1001200102120220201022 |
4 | 22112111232222023 |
5 | 140224211310011 |
6 | 5034353143055 |
7 | 542241152555 |
oct | 122625565213 |
9 | 31612526638 |
10 | 11112213131 |
11 | 4792611218 |
12 | 21a155aa8b |
13 | 1081256156 |
14 | 775b604d5 |
15 | 4508578db |
hex | 29656ea8b |
11112213131 has 2 divisors, whose sum is σ = 11112213132. Its totient is φ = 11112213130.
The previous prime is 11112213083. The next prime is 11112213139. The reversal of 11112213131 is 13131221111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11112213131 is a prime.
It is a super-2 number, since 2×111122131312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11112213139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556106565 + 5556106566.
It is an arithmetic number, because the mean of its divisors is an integer number (5556106566).
Almost surely, 211112213131 is an apocalyptic number.
11112213131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112213131 is an equidigital number, since it uses as much as digits as its factorization.
11112213131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36, while the sum is 17.
Adding to 11112213131 its reverse (13131221111), we get a palindrome (24243434242).
The spelling of 11112213131 in words is "eleven billion, one hundred twelve million, two hundred thirteen thousand, one hundred thirty-one".
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