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111122143001 = 731522221137
BaseRepresentation
bin110011101111101100…
…1010101011100011001
3101121211021220202011222
41213133121111130121
53310034232034001
6123014313101425
711012465426252
oct1473731253431
9347737822158
10111122143001
1143143609821
12196526b7875
13a62bb3154c
145542247b29
152d558a461b
hex19df655719

111122143001 has 4 divisors (see below), whose sum is σ = 112644364212. Its totient is φ = 109599921792.

The previous prime is 111122142997. The next prime is 111122143003. The reversal of 111122143001 is 100341221111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 78707741401 + 32414401600 = 280549^2 + 180040^2 .

It is a cyclic number.

It is not a de Polignac number, because 111122143001 - 22 = 111122142997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (111122143003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 761110496 + ... + 761110641.

It is an arithmetic number, because the mean of its divisors is an integer number (28161091053).

Almost surely, 2111122143001 is an apocalyptic number.

It is an amenable number.

111122143001 is a deficient number, since it is larger than the sum of its proper divisors (1522221211).

111122143001 is an equidigital number, since it uses as much as digits as its factorization.

111122143001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1522221210.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 111122143001 its reverse (100341221111), we get a palindrome (211463364112).

The spelling of 111122143001 in words is "one hundred eleven billion, one hundred twenty-two million, one hundred forty-three thousand, one".

Divisors: 1 73 1522221137 111122143001