111122200020133 has 2 divisors, whose sum is σ = 111122200020134. Its totient is φ = 111122200020132.

The previous prime is 111122200020127. The next prime is 111122200020151. The reversal of 111122200020133 is 331020002221111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105421289295169 + 5700910724964 = 10267487^2 + 2387658^2 .

It is a cyclic number.

It is not a de Polignac number, because 111122200020133 - 2⁵ = 111122200020101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111122200020133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111122200020163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55561100010066 + 55561100010067.

It is an arithmetic number, because the mean of its divisors is an integer number (55561100010067).

Almost surely, 2^{111122200020133} is an apocalyptic number.

It is an amenable number.

111122200020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

111122200020133 is an equidigital number, since it uses as much as digits as its factorization.

111122200020133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 111122200020133 its reverse (331020002221111), we get a palindrome (442142202241244).

The spelling of 111122200020133 in words is "one hundred eleven trillion, one hundred twenty-two billion, two hundred million, twenty thousand, one hundred thirty-three".