Base | Representation |
---|---|
bin | 1010000110110100001111… |
… | …1111100011110110010100 |
3 | 1110100022120210111202102110 |
4 | 2201231003333203312110 |
5 | 2424030312102131012 |
6 | 35344514531511020 |
7 | 2224555125066663 |
oct | 241550377436624 |
9 | 43308523452373 |
10 | 11112221130132 |
11 | 35a4737150a61 |
12 | 12b5758458470 |
13 | 627b54b40235 |
14 | 2a5b97736dda |
15 | 1440c379473c |
hex | a1b43fe3d94 |
11112221130132 has 24 divisors (see below), whose sum is σ = 25928882174272. Its totient is φ = 3704021395200.
The previous prime is 11112221130097. The next prime is 11112221130133. The reversal of 11112221130132 is 23103112221111.
It is a junction number, because it is equal to n+sod(n) for n = 11112221130099 and 11112221130108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11112221130133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5649469 + ... + 7358052.
Almost surely, 211112221130132 is an apocalyptic number.
11112221130132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11112221130132 is an abundant number, since it is smaller than the sum of its proper divisors (14816661044140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11112221130132 is a wasteful number, since it uses less digits than its factorization.
11112221130132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13078719 (or 13078717 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 11112221130132 its reverse (23103112221111), we get a palindrome (34215333351243).
The spelling of 11112221130132 in words is "eleven trillion, one hundred twelve billion, two hundred twenty-one million, one hundred thirty thousand, one hundred thirty-two".
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