Base | Representation |
---|---|
bin | 10000001010111010001… |
… | …001001110100001101111 |
3 | 10221020021011000122112021 |
4 | 100022322021032201233 |
5 | 121201241440341333 |
6 | 2210253422251011 |
7 | 143166115525465 |
oct | 20127211164157 |
9 | 3836234018467 |
10 | 1111224543343 |
11 | 3992a43155a2 |
12 | 15b442a26a67 |
13 | 80a323a12b5 |
14 | 3bad8108835 |
15 | 1dd8b0e682d |
hex | 102ba24e86f |
1111224543343 has 2 divisors, whose sum is σ = 1111224543344. Its totient is φ = 1111224543342.
The previous prime is 1111224543311. The next prime is 1111224543361. The reversal of 1111224543343 is 3433454221111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1111224543343 - 25 = 1111224543311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1111224543299 and 1111224543308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111224543383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555612271671 + 555612271672.
It is an arithmetic number, because the mean of its divisors is an integer number (555612271672).
Almost surely, 21111224543343 is an apocalyptic number.
1111224543343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111224543343 is an equidigital number, since it uses as much as digits as its factorization.
1111224543343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 34560, while the sum is 34.
Adding to 1111224543343 its reverse (3433454221111), we get a palindrome (4544678764454).
The spelling of 1111224543343 in words is "one trillion, one hundred eleven billion, two hundred twenty-four million, five hundred forty-three thousand, three hundred forty-three".
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