Base | Representation |
---|---|
bin | 10000001010111010011… |
… | …110000010110100010011 |
3 | 10221020021112021220012121 |
4 | 100022322132002310103 |
5 | 121201244340003103 |
6 | 2210254135235111 |
7 | 143166213104335 |
oct | 20127236026423 |
9 | 3836245256177 |
10 | 1111230000403 |
11 | 3992a7402566 |
12 | 15b444818a97 |
13 | 80a33562123 |
14 | 3bad8b29455 |
15 | 1dd8b8236bd |
hex | 102ba782d13 |
1111230000403 has 2 divisors, whose sum is σ = 1111230000404. Its totient is φ = 1111230000402.
The previous prime is 1111230000371. The next prime is 1111230000427. The reversal of 1111230000403 is 3040000321111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1111230000403 - 25 = 1111230000371 is a prime.
It is a super-2 number, since 2×11112300004032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1111230000473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555615000201 + 555615000202.
It is an arithmetic number, because the mean of its divisors is an integer number (555615000202).
Almost surely, 21111230000403 is an apocalyptic number.
1111230000403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111230000403 is an equidigital number, since it uses as much as digits as its factorization.
1111230000403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1111230000403 its reverse (3040000321111), we get a palindrome (4151230321514).
The spelling of 1111230000403 in words is "one trillion, one hundred eleven billion, two hundred thirty million, four hundred three", and thus it is an aban number.
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