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111123000257 is a prime number
BaseRepresentation
bin110011101111101110…
…0100110101111000001
3101121211100112022010012
41213133130212233001
53310034442002012
6123014343314305
711012505626453
oct1473734465701
9347740468105
10111123000257
11431440448a5
1219652a4b995
13a62c0717b9
1455423cc2d3
152d559c3622
hex19df726bc1

111123000257 has 2 divisors, whose sum is σ = 111123000258. Its totient is φ = 111123000256.

The previous prime is 111123000143. The next prime is 111123000301. The reversal of 111123000257 is 752000321111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91855061776 + 19267938481 = 303076^2 + 138809^2 .

It is a cyclic number.

It is not a de Polignac number, because 111123000257 - 222 = 111118805953 is a prime.

It is a super-2 number, since 2×1111230002572 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111123008257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55561500128 + 55561500129.

It is an arithmetic number, because the mean of its divisors is an integer number (55561500129).

Almost surely, 2111123000257 is an apocalyptic number.

It is an amenable number.

111123000257 is a deficient number, since it is larger than the sum of its proper divisors (1).

111123000257 is an equidigital number, since it uses as much as digits as its factorization.

111123000257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 23.

Adding to 111123000257 its reverse (752000321111), we get a palindrome (863123321368).

The spelling of 111123000257 in words is "one hundred eleven billion, one hundred twenty-three million, two hundred fifty-seven", and thus it is an aban number.