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11112543133 = 109101949937
BaseRepresentation
bin10100101100101101…
…11111001110011101
31001200110012200101121
422112112333032131
5140224302340013
65034404210541
7542244025636
oct122626771635
931613180347
1011112543133
11479281714a
1221a1699a51
131081340413
14775c0888d
154508c058d
hex2965bf39d

11112543133 has 4 divisors (see below), whose sum is σ = 11214493180. Its totient is φ = 11010593088.

The previous prime is 11112543131. The next prime is 11112543149. The reversal of 11112543133 is 33134521111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5226277849 + 5886265284 = 72293^2 + 76722^2 .

It is a cyclic number.

It is not a de Polignac number, because 11112543133 - 21 = 11112543131 is a prime.

It is a super-2 number, since 2×111125431332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11112543098 and 11112543107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11112543131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50974860 + ... + 50975077.

It is an arithmetic number, because the mean of its divisors is an integer number (2803623295).

Almost surely, 211112543133 is an apocalyptic number.

It is an amenable number.

11112543133 is a deficient number, since it is larger than the sum of its proper divisors (101950047).

11112543133 is a wasteful number, since it uses less digits than its factorization.

11112543133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101950046.

The product of its digits is 1080, while the sum is 25.

The spelling of 11112543133 in words is "eleven billion, one hundred twelve million, five hundred forty-three thousand, one hundred thirty-three".

Divisors: 1 109 101949937 11112543133