Base | Representation |
---|---|
bin | 10100101100101110… |
… | …00001011001100001 |
3 | 1001200110020010121020 |
4 | 22112113001121201 |
5 | 140224303131113 |
6 | 5034404320053 |
7 | 542244063612 |
oct | 122627013141 |
9 | 31613203536 |
10 | 11112552033 |
11 | 4792822900 |
12 | 21a16a3029 |
13 | 108134449b |
14 | 775c0bc09 |
15 | 4508c3023 |
hex | 2965c1661 |
11112552033 has 24 divisors (see below), whose sum is σ = 16299411744. Its totient is φ = 6729402240.
The previous prime is 11112552023. The next prime is 11112552037. The reversal of 11112552033 is 33025521111.
It is not a de Polignac number, because 11112552033 - 26 = 11112551969 is a prime.
It is a super-2 number, since 2×111125520332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11112551994 and 11112552012.
It is not an unprimeable number, because it can be changed into a prime (11112552037) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 459010 + ... + 482612.
It is an arithmetic number, because the mean of its divisors is an integer number (679142156).
Almost surely, 211112552033 is an apocalyptic number.
It is an amenable number.
11112552033 is a deficient number, since it is larger than the sum of its proper divisors (5186859711).
11112552033 is a wasteful number, since it uses less digits than its factorization.
11112552033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24925 (or 24914 counting only the distinct ones).
The product of its (nonzero) digits is 900, while the sum is 24.
The spelling of 11112552033 in words is "eleven billion, one hundred twelve million, five hundred fifty-two thousand, thirty-three".
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