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111130011113 = 1111113909091
BaseRepresentation
bin110011101111111011…
…1010110010111101001
3101121211211201111012112
41213133313112113221
53310043240323423
6123015153452105
711012622336332
oct1473767262751
9347754644175
10111130011113
1143147aa31a0
1219655271035
13a630657934
1455432d5289
152d5640aa78
hex19dfdd65e9

111130011113 has 8 divisors (see below), whose sum is σ = 121243781856. Its totient is φ = 101018080800.

The previous prime is 111130011101. The next prime is 111130011127. The reversal of 111130011113 is 311110031111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 111130011113 - 212 = 111130007017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111130011413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 332303 + ... + 576788.

It is an arithmetic number, because the mean of its divisors is an integer number (15155472732).

Almost surely, 2111130011113 is an apocalyptic number.

It is an amenable number.

111130011113 is a deficient number, since it is larger than the sum of its proper divisors (10113770743).

111130011113 is a wasteful number, since it uses less digits than its factorization.

111130011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 920215.

The product of its (nonzero) digits is 9, while the sum is 14.

Adding to 111130011113 its reverse (311110031111), we get a palindrome (422240042224).

It can be divided in two parts, 1111300 and 11113, that multiplied together give a square (12349876900 = 1111302).

The spelling of 111130011113 in words is "one hundred eleven billion, one hundred thirty million, eleven thousand, one hundred thirteen".

Divisors: 1 11 11113 122243 909091 10000001 10102728283 111130011113