11113023113 has 4 divisors (see below), whose sum is σ = 11200527360. Its totient is φ = 11025518868.

The previous prime is 11113023083. The next prime is 11113023143. The reversal of 11113023113 is 31132031111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31132031111 = 137 ⋅227241103.

It is an interprime number because it is at equal distance from previous prime (11113023083) and next prime (11113023143).

It is a cyclic number.

It is not a de Polignac number, because 11113023113 - 2⁶ = 11113023049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11113023091 and 11113023100.

It is not an unprimeable number, because it can be changed into a prime (11113023143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43751933 + ... + 43752186.

It is an arithmetic number, because the mean of its divisors is an integer number (2800131840).

Almost surely, 2^11113023113 is an apocalyptic number.

It is an amenable number.

11113023113 is a deficient number, since it is larger than the sum of its proper divisors (87504247).

11113023113 is an equidigital number, since it uses as much as digits as its factorization.

11113023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87504246.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11113023113 its reverse (31132031111), we get a palindrome (42245054224).

The spelling of 11113023113 in words is "eleven billion, one hundred thirteen million, twenty-three thousand, one hundred thirteen".