11113112213130 has 64 divisors (see below), whose sum is σ = 27593669174400. Its totient is φ = 2861048413440.

The previous prime is 11113112213111. The next prime is 11113112213141. The reversal of 11113112213130 is 3131221131111.

It is a super-3 number, since 3×11113112213130³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11113112213097 and 11113112213106.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9147036 + ... + 10290504.

It is an arithmetic number, because the mean of its divisors is an integer number (431151080850).

Almost surely, 2^{11113112213130} is an apocalyptic number.

11113112213130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11113112213130 is an abundant number, since it is smaller than the sum of its proper divisors (16480556961270).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11113112213130 is a wasteful number, since it uses less digits than its factorization.

11113112213130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1154679.

The product of its (nonzero) digits is 108, while the sum is 21.

Adding to 11113112213130 its reverse (3131221131111), we get a palindrome (14244333344241).

The spelling of 11113112213130 in words is "eleven trillion, one hundred thirteen billion, one hundred twelve million, two hundred thirteen thousand, one hundred thirty".