11113113103 has 2 divisors, whose sum is σ = 11113113104. Its totient is φ = 11113113102.

The previous prime is 11113113097. The next prime is 11113113131. The reversal of 11113113103 is 30131131111.

It is a weak prime.

It is an emirp because it is prime and its reverse (30131131111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11113113103 - 2²⁵ = 11079558671 is a prime.

It is a super-3 number, since 3×11113113103³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11113113703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556556551 + 5556556552.

It is an arithmetic number, because the mean of its divisors is an integer number (5556556552).

Almost surely, 2^11113113103 is an apocalyptic number.

11113113103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113113103 is an equidigital number, since it uses as much as digits as its factorization.

11113113103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 11113113103 its reverse (30131131111), we get a palindrome (41244244214).

The spelling of 11113113103 in words is "eleven billion, one hundred thirteen million, one hundred thirteen thousand, one hundred three".