Base | Representation |
---|---|
bin | 1010000110110111100100… |
… | …1010100111101110001111 |
3 | 1110100101212222010201110011 |
4 | 2201231321022213232033 |
5 | 2424034123441101111 |
6 | 35345143240254051 |
7 | 2224616206541002 |
oct | 241557112475617 |
9 | 43311788121404 |
10 | 11113113222031 |
11 | 35a5054771897 |
12 | 12b5967171327 |
13 | 627c678c8272 |
14 | 2a5c3ddd5539 |
15 | 144126c5d021 |
hex | a1b792a7b8f |
11113113222031 has 2 divisors, whose sum is σ = 11113113222032. Its totient is φ = 11113113222030.
The previous prime is 11113113222023. The next prime is 11113113222037. The reversal of 11113113222031 is 13022231131111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11113113222031 - 23 = 11113113222023 is a prime.
It is a super-2 number, since 2×111131132220312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11113113221993 and 11113113222011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11113113222037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556556611015 + 5556556611016.
It is an arithmetic number, because the mean of its divisors is an integer number (5556556611016).
Almost surely, 211113113222031 is an apocalyptic number.
11113113222031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113113222031 is an equidigital number, since it uses as much as digits as its factorization.
11113113222031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 11113113222031 its reverse (13022231131111), we get a palindrome (24135344353142).
The spelling of 11113113222031 in words is "eleven trillion, one hundred thirteen billion, one hundred thirteen million, two hundred twenty-two thousand, thirty-one".
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