Base | Representation |
---|---|
bin | 11001010001001010111111… |
… | …110100110100110111101010 |
3 | 112120111001001112220010020201 |
4 | 121101022333310310313222 |
5 | 104031233200220104002 |
6 | 1032204545222542414 |
7 | 32256651534031561 |
oct | 3121127764646752 |
9 | 476431045803221 |
10 | 111131202113002 |
11 | 32456529454535 |
12 | 10569b7a897a0a |
13 | 4a018204c5996 |
14 | 1d62ac9372bd8 |
15 | ccab9e5e4087 |
hex | 6512bfd34dea |
111131202113002 has 4 divisors (see below), whose sum is σ = 166696803169506. Its totient is φ = 55565601056500.
The previous prime is 111131202112979. The next prime is 111131202113021. The reversal of 111131202113002 is 200311202131111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 100455697972081 + 10675504140921 = 10022759^2 + 3267339^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27782800528249 + ... + 27782800528252.
Almost surely, 2111131202113002 is an apocalyptic number.
111131202113002 is a deficient number, since it is larger than the sum of its proper divisors (55565601056504).
111131202113002 is an equidigital number, since it uses as much as digits as its factorization.
111131202113002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55565601056503.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 111131202113002 its reverse (200311202131111), we get a palindrome (311442404244113).
The spelling of 111131202113002 in words is "one hundred eleven trillion, one hundred thirty-one billion, two hundred two million, one hundred thirteen thousand, two".
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