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11113142201449 is a prime number
BaseRepresentation
bin1010000110110111101011…
…1001001010110001101001
31110100101221222200000201221
42201231322321022301221
52424034203400421244
635345150153342041
72224620011056051
oct241557271126151
943311858600657
1011113142201449
1135a506a065522
1212b5974a07921
13627c70903852
142a5c43bba561
15144129584784
hexa1b7ae4ac69

11113142201449 has 2 divisors, whose sum is σ = 11113142201450. Its totient is φ = 11113142201448.

The previous prime is 11113142201401. The next prime is 11113142201477. The reversal of 11113142201449 is 94410224131111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6772719978025 + 4340422223424 = 2602445^2 + 2083368^2 .

It is a cyclic number.

It is not a de Polignac number, because 11113142201449 - 27 = 11113142201321 is a prime.

It is a super-4 number, since 4×111131422014494 (a number of 53 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (11113142208449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556571100724 + 5556571100725.

It is an arithmetic number, because the mean of its divisors is an integer number (5556571100725).

Almost surely, 211113142201449 is an apocalyptic number.

It is an amenable number.

11113142201449 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113142201449 is an equidigital number, since it uses as much as digits as its factorization.

11113142201449 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 34.

The spelling of 11113142201449 in words is "eleven trillion, one hundred thirteen billion, one hundred forty-two million, two hundred one thousand, four hundred forty-nine".