Base | Representation |
---|---|
bin | 1010000110110111111010… |
… | …0001111110100111110111 |
3 | 1110100102010020111122211221 |
4 | 2201231332201332213313 |
5 | 2424034320011344343 |
6 | 35345200213411211 |
7 | 2224621351602322 |
oct | 241557641764767 |
9 | 43312106448757 |
10 | 11113203231223 |
11 | 35a50a055a055 |
12 | 12b5991339b07 |
13 | 627c80451442 |
14 | 2a5c4bd457b9 |
15 | 14412eadc5ed |
hex | a1b7e87e9f7 |
11113203231223 has 4 divisors (see below), whose sum is σ = 11215159224280. Its totient is φ = 11011247238168.
The previous prime is 11113203231197. The next prime is 11113203231253. The reversal of 11113203231223 is 32213230231111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11113203231223 - 25 = 11113203231191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11113203231253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50977996365 + ... + 50977996582.
It is an arithmetic number, because the mean of its divisors is an integer number (2803789806070).
Almost surely, 211113203231223 is an apocalyptic number.
11113203231223 is a deficient number, since it is larger than the sum of its proper divisors (101955993057).
11113203231223 is a wasteful number, since it uses less digits than its factorization.
11113203231223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101955993056.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11113203231223 its reverse (32213230231111), we get a palindrome (43326433462334).
The spelling of 11113203231223 in words is "eleven trillion, one hundred thirteen billion, two hundred three million, two hundred thirty-one thousand, two hundred twenty-three".
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