111132220023133 has 4 divisors (see below), whose sum is σ = 111132243171520. Its totient is φ = 111132196874748.

The previous prime is 111132220023107. The next prime is 111132220023203. The reversal of 111132220023133 is 331320022231111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111132220023133 - 2⁵ = 111132220023101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111132220023098 and 111132220023107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111132220053133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1379973 + ... + 14972266.

It is an arithmetic number, because the mean of its divisors is an integer number (27783060792880).

Almost surely, 2^{111132220023133} is an apocalyptic number.

It is an amenable number.

111132220023133 is a deficient number, since it is larger than the sum of its proper divisors (23148387).

111132220023133 is an equidigital number, since it uses as much as digits as its factorization.

111132220023133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23148386.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 111132220023133 its reverse (331320022231111), we get a palindrome (442452242254244).

The spelling of 111132220023133 in words is "one hundred eleven trillion, one hundred thirty-two billion, two hundred twenty million, twenty-three thousand, one hundred thirty-three".