111133110000001 has 4 divisors (see below), whose sum is σ = 111133135095472. Its totient is φ = 111133084904532.

The previous prime is 111133109999981. The next prime is 111133110000007. The reversal of 111133110000001 is 100000011331111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111133110000001 - 2¹⁷ = 111133109868929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111133110000007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3934131 + ... + 15418936.

It is an arithmetic number, because the mean of its divisors is an integer number (27783283773868).

Almost surely, 2^{111133110000001} is an apocalyptic number.

It is an amenable number.

111133110000001 is a deficient number, since it is larger than the sum of its proper divisors (25095471).

111133110000001 is an equidigital number, since it uses as much as digits as its factorization.

111133110000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25095470.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 111133110000001 its reverse (100000011331111), we get a palindrome (211133121331112).

The spelling of 111133110000001 in words is "one hundred eleven trillion, one hundred thirty-three billion, one hundred ten million, one", and thus it is an aban number.