11113353433135 has 16 divisors (see below), whose sum is σ = 13368997404000. Its totient is φ = 8868717221760.

The previous prime is 11113353433097. The next prime is 11113353433139. The reversal of 11113353433135 is 53133435331111.

It is a de Polignac number, because none of the positive numbers 2^k-11113353433135 is a prime.

It is a super-3 number, since 3×11113353433135³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11113353433094 and 11113353433103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11113353433139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4301569 + ... + 6382021.

It is an arithmetic number, because the mean of its divisors is an integer number (835562337750).

Almost surely, 2^{11113353433135} is an apocalyptic number.

11113353433135 is a deficient number, since it is larger than the sum of its proper divisors (2255643970865).

11113353433135 is a wasteful number, since it uses less digits than its factorization.

11113353433135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2083098.

The product of its digits is 72900, while the sum is 37.

Adding to 11113353433135 its reverse (53133435331111), we get a palindrome (64246788764246).

The spelling of 11113353433135 in words is "eleven trillion, one hundred thirteen billion, three hundred fifty-three million, four hundred thirty-three thousand, one hundred thirty-five".