Base | Representation |
---|---|
bin | 10000001011000001001… |
… | …101001001110010001011 |
3 | 10221020120101221112100110 |
4 | 100023001031021302023 |
5 | 121202012302404003 |
6 | 2210313253405403 |
7 | 143202054514206 |
oct | 20130115116213 |
9 | 3836511845313 |
10 | 1111343013003 |
11 | 399355181603 |
12 | 15b476639863 |
13 | 80a50ab07a2 |
14 | 3bb09b4693d |
15 | 1dd966e8a03 |
hex | 102c1349c8b |
1111343013003 has 64 divisors (see below), whose sum is σ = 1560748400640. Its totient is φ = 702530841600.
The previous prime is 1111343012999. The next prime is 1111343013041. The reversal of 1111343013003 is 3003103431111.
It is not a de Polignac number, because 1111343013003 - 22 = 1111343012999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1111343013103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1296782551 + ... + 1296783407.
It is an arithmetic number, because the mean of its divisors is an integer number (24386693760).
Almost surely, 21111343013003 is an apocalyptic number.
1111343013003 is a deficient number, since it is larger than the sum of its proper divisors (449405387637).
1111343013003 is a wasteful number, since it uses less digits than its factorization.
1111343013003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1948.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 1111343013003 its reverse (3003103431111), we get a palindrome (4114446444114).
The spelling of 1111343013003 in words is "one trillion, one hundred eleven billion, three hundred forty-three million, thirteen thousand, three".
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