1111400153 has 2 divisors, whose sum is σ = 1111400154. Its totient is φ = 1111400152.

The previous prime is 1111400093. The next prime is 1111400183. The reversal of 1111400153 is 3510041111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 737828569 + 373571584 = 27163^2 + 19328^2 .

It is an emirp because it is prime and its reverse (3510041111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111400153 - 2¹² = 1111396057 is a prime.

It is not a weakly prime, because it can be changed into another prime (1111400183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555700076 + 555700077.

It is an arithmetic number, because the mean of its divisors is an integer number (555700077).

Almost surely, 2^1111400153 is an apocalyptic number.

It is an amenable number.

1111400153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111400153 is an equidigital number, since it uses as much as digits as its factorization.

1111400153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 1111400153 is about 33337.6686797382. The cubic root of 1111400153 is about 1035.8339728999.

Adding to 1111400153 its reverse (3510041111), we get a palindrome (4621441264).

The spelling of 1111400153 in words is "one billion, one hundred eleven million, four hundred thousand, one hundred fifty-three".