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11114083 = 23483221
BaseRepresentation
bin101010011001…
…011001100011
3202220122122201
4222121121203
510321122313
61034114031
7163316401
oct52313143
922818581
1011114083
1163011a2
12387b917
1323c19a6
141694471
15e980dd
hexa99663

11114083 has 4 divisors (see below), whose sum is σ = 11597328. Its totient is φ = 10630840.

The previous prime is 11113933. The next prime is 11114087. The reversal of 11114083 is 38041111.

11114083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11114083 is a prime.

It is a Duffinian number.

It is a nialpdrome in base 16.

It is a self number, because there is not a number n which added to its sum of digits gives 11114083.

It is not an unprimeable number, because it can be changed into a prime (11114087) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241588 + ... + 241633.

It is an arithmetic number, because the mean of its divisors is an integer number (2899332).

Almost surely, 211114083 is an apocalyptic number.

11114083 is a deficient number, since it is larger than the sum of its proper divisors (483245).

11114083 is an equidigital number, since it uses as much as digits as its factorization.

11114083 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 483244.

The product of its (nonzero) digits is 96, while the sum is 19.

The square root of 11114083 is about 3333.7790868622. The cubic root of 11114083 is about 223.1642097240.

Adding to 11114083 its reverse (38041111), we get a palindrome (49155194).

The spelling of 11114083 in words is "eleven million, one hundred fourteen thousand, eighty-three".

Divisors: 1 23 483221 11114083