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11114132523139 is a prime number
BaseRepresentation
bin1010000110111011010111…
…1010111100100010000011
31110100111112000010120201001
42201232311322330202003
52424043220411220024
635345432331352431
72224653364500232
oct241566572744203
943314460116631
1011114132523139
1135a55280788a8
1212b5bb05b2717
1362809ab32709
142a5cd9528b19
151441864a3244
hexa1bb5ebc883

11114132523139 has 2 divisors, whose sum is σ = 11114132523140. Its totient is φ = 11114132523138.

The previous prime is 11114132523127. The next prime is 11114132523167. The reversal of 11114132523139 is 93132523141111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11114132523139 - 211 = 11114132521091 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11114132523098 and 11114132523107.

It is not a weakly prime, because it can be changed into another prime (11114132523119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557066261569 + 5557066261570.

It is an arithmetic number, because the mean of its divisors is an integer number (5557066261570).

Almost surely, 211114132523139 is an apocalyptic number.

11114132523139 is a deficient number, since it is larger than the sum of its proper divisors (1).

11114132523139 is an equidigital number, since it uses as much as digits as its factorization.

11114132523139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19440, while the sum is 37.

The spelling of 11114132523139 in words is "eleven trillion, one hundred fourteen billion, one hundred thirty-two million, five hundred twenty-three thousand, one hundred thirty-nine".