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111143221403134 = 2349115918536437
BaseRepresentation
bin11001010001010110001100…
…001110110001110111111110
3112120112012002012022022200111
4121101112030032301313332
5104031432304134400014
61032214254022020234
732260555431230014
oct3121261416616776
9476465065268614
10111143221403134
1132460636a91068
1210570373b7767a
134a029b765278b
141d635097728b4
15ccb1548c52c4
hex65158c3b1dfe

111143221403134 has 8 divisors (see below), whose sum is σ = 166762587724488. Its totient is φ = 55555692161640.

The previous prime is 111143221403129. The next prime is 111143221403209. The reversal of 111143221403134 is 431304122341111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 111143221403096 and 111143221403105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7959261237 + ... + 7959275200.

It is an arithmetic number, because the mean of its divisors is an integer number (20845323465561).

Almost surely, 2111143221403134 is an apocalyptic number.

111143221403134 is a deficient number, since it is larger than the sum of its proper divisors (55619366321354).

111143221403134 is a wasteful number, since it uses less digits than its factorization.

111143221403134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15918539930.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 111143221403134 its reverse (431304122341111), we get a palindrome (542447343744245).

The spelling of 111143221403134 in words is "one hundred eleven trillion, one hundred forty-three billion, two hundred twenty-one million, four hundred three thousand, one hundred thirty-four".

Divisors: 1 2 3491 6982 15918536437 31837072874 55571610701567 111143221403134