Base | Representation |
---|---|
bin | 10100101100111011… |
… | …10010000101100011 |
3 | 1001200120120011201121 |
4 | 22112131302011203 |
5 | 140230231334243 |
6 | 5034510313111 |
7 | 542265124624 |
oct | 122635620543 |
9 | 31616504647 |
10 | 11114324323 |
11 | 4793823403 |
12 | 21a21b8797 |
13 | 108181508b |
14 | 77614da4b |
15 | 450b231ed |
hex | 296772163 |
11114324323 has 2 divisors, whose sum is σ = 11114324324. Its totient is φ = 11114324322.
The previous prime is 11114324297. The next prime is 11114324371. The reversal of 11114324323 is 32342341111.
11114324323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (32342341111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11114324323 - 29 = 11114323811 is a prime.
It is not a weakly prime, because it can be changed into another prime (11114324393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557162161 + 5557162162.
It is an arithmetic number, because the mean of its divisors is an integer number (5557162162).
Almost surely, 211114324323 is an apocalyptic number.
11114324323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11114324323 is an equidigital number, since it uses as much as digits as its factorization.
11114324323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 25.
Adding to 11114324323 its reverse (32342341111), we get a palindrome (43456665434).
The spelling of 11114324323 in words is "eleven billion, one hundred fourteen million, three hundred twenty-four thousand, three hundred twenty-three".
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