111144014311081 has 2 divisors, whose sum is σ = 111144014311082. Its totient is φ = 111144014311080.

The previous prime is 111144014311069. The next prime is 111144014311097. The reversal of 111144014311081 is 180113410441111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102237275450025 + 8906738861056 = 10111245^2 + 2984416^2 .

It is a cyclic number.

It is not a de Polignac number, because 111144014311081 - 2¹⁵ = 111144014278313 is a prime.

It is a super-3 number, since 3×111144014311081³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (111144014318081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55572007155540 + 55572007155541.

It is an arithmetic number, because the mean of its divisors is an integer number (55572007155541).

Almost surely, 2^{111144014311081} is an apocalyptic number.

It is an amenable number.

111144014311081 is a deficient number, since it is larger than the sum of its proper divisors (1).

111144014311081 is an equidigital number, since it uses as much as digits as its factorization.

111144014311081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 31.

Adding to 111144014311081 its reverse (180113410441111), we get a palindrome (291257424752192).

The spelling of 111144014311081 in words is "one hundred eleven trillion, one hundred forty-four billion, fourteen million, three hundred eleven thousand, eighty-one".