111144412741153 has 4 divisors (see below), whose sum is σ = 121248450263088. Its totient is φ = 101040375219220.

The previous prime is 111144412741129. The next prime is 111144412741177. The reversal of 111144412741153 is 351147214441111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (111144412741129) and next prime (111144412741177).

It is a cyclic number.

It is not a de Polignac number, because 111144412741153 - 2⁵ = 111144412741121 is a prime.

It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111144412241153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5052018760951 + ... + 5052018760972.

It is an arithmetic number, because the mean of its divisors is an integer number (30312112565772).

Almost surely, 2^{111144412741153} is an apocalyptic number.

It is an amenable number.

111144412741153 is a deficient number, since it is larger than the sum of its proper divisors (10104037521935).

111144412741153 is a wasteful number, since it uses less digits than its factorization.

111144412741153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10104037521934.

The product of its digits is 53760, while the sum is 40.

The spelling of 111144412741153 in words is "one hundred eleven trillion, one hundred forty-four billion, four hundred twelve million, seven hundred forty-one thousand, one hundred fifty-three".