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11115205112131 is a prime number
BaseRepresentation
bin1010000110111111010111…
…0110100011000101000011
31110100121021202101202012021
42201233311312203011003
52424102420002042011
635350131004542311
72225022100366651
oct241576566430503
943317252352167
1011115205112131
1135a5a2857088a
1212b624b851997
1362820c106963
142a5d9bb6ddd1
151441ea722471
hexa1bf5da3143

11115205112131 has 2 divisors, whose sum is σ = 11115205112132. Its totient is φ = 11115205112130.

The previous prime is 11115205112111. The next prime is 11115205112153. The reversal of 11115205112131 is 13121150251111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11115205112131 - 231 = 11113057628483 is a prime.

It is a super-2 number, since 2×111152051121312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11115205112096 and 11115205112105.

It is not a weakly prime, because it can be changed into another prime (11115205112101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557602556065 + 5557602556066.

It is an arithmetic number, because the mean of its divisors is an integer number (5557602556066).

Almost surely, 211115205112131 is an apocalyptic number.

11115205112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11115205112131 is an equidigital number, since it uses as much as digits as its factorization.

11115205112131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 300, while the sum is 25.

Adding to 11115205112131 its reverse (13121150251111), we get a palindrome (24236355363242).

The spelling of 11115205112131 in words is "eleven trillion, one hundred fifteen billion, two hundred five million, one hundred twelve thousand, one hundred thirty-one".