Base | Representation |
---|---|
bin | 110011110000110111… |
… | …0000010100101001001 |
3 | 101121221000021020200212 |
4 | 1213201232002211021 |
5 | 3310124222001233 |
6 | 123022224410505 |
7 | 11013450655046 |
oct | 1474156024511 |
9 | 347830236625 |
10 | 111161125193 |
11 | 43163614708 |
12 | 19663776a35 |
13 | a636c2ca31 |
14 | 55474b41cd |
15 | 2d59004a48 |
hex | 19e1b82949 |
111161125193 has 2 divisors, whose sum is σ = 111161125194. Its totient is φ = 111161125192.
The previous prime is 111161125171. The next prime is 111161125211. The reversal of 111161125193 is 391521161111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95649169984 + 15511955209 = 309272^2 + 124547^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111161125193 is a prime.
It is not a weakly prime, because it can be changed into another prime (111161125993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55580562596 + 55580562597.
It is an arithmetic number, because the mean of its divisors is an integer number (55580562597).
Almost surely, 2111161125193 is an apocalyptic number.
It is an amenable number.
111161125193 is a deficient number, since it is larger than the sum of its proper divisors (1).
111161125193 is an equidigital number, since it uses as much as digits as its factorization.
111161125193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1620, while the sum is 32.
The spelling of 111161125193 in words is "one hundred eleven billion, one hundred sixty-one million, one hundred twenty-five thousand, one hundred ninety-three".
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