Base | Representation |
---|---|
bin | 1010000111000011111001… |
… | …1100110110001100111011 |
3 | 1110100201102122021112012101 |
4 | 2201300332130312030323 |
5 | 2424112413304031413 |
6 | 35350451514524231 |
7 | 2225064220252324 |
oct | 241607634661473 |
9 | 43321378245171 |
10 | 11116423111483 |
11 | 35a64a3050818 |
12 | 12b652b736677 |
13 | 628374560a31 |
14 | 2a607582744b |
15 | 14426c615edd |
hex | a1c3e73633b |
11116423111483 has 2 divisors, whose sum is σ = 11116423111484. Its totient is φ = 11116423111482.
The previous prime is 11116423111481. The next prime is 11116423111579. The reversal of 11116423111483 is 38411132461111.
It is a weak prime.
It is an emirp because it is prime and its reverse (38411132461111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11116423111483 - 21 = 11116423111481 is a prime.
Together with 11116423111481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11116423111481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5558211555741 + 5558211555742.
It is an arithmetic number, because the mean of its divisors is an integer number (5558211555742).
Almost surely, 211116423111483 is an apocalyptic number.
11116423111483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11116423111483 is an equidigital number, since it uses as much as digits as its factorization.
11116423111483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824, while the sum is 37.
Adding to 11116423111483 its reverse (38411132461111), we get a palindrome (49527555572594).
The spelling of 11116423111483 in words is "eleven trillion, one hundred sixteen billion, four hundred twenty-three million, one hundred eleven thousand, four hundred eighty-three".
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