11120000113 has 2 divisors, whose sum is σ = 11120000114. Its totient is φ = 11120000112.

The previous prime is 11120000093. The next prime is 11120000123. The reversal of 11120000113 is 31100002111.

It is an a-pointer prime, because the next prime (11120000123) can be obtained adding 11120000113 to its sum of digits (10).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9160786944 + 1959213169 = 95712^2 + 44263^2 .

It is an emirp because it is prime and its reverse (31100002111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11120000113 - 2⁹ = 11119999601 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11120000113.

It is not a weakly prime, because it can be changed into another prime (11120000123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560000056 + 5560000057.

It is an arithmetic number, because the mean of its divisors is an integer number (5560000057).

Almost surely, 2^11120000113 is an apocalyptic number.

It is an amenable number.

11120000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120000113 is an equidigital number, since it uses as much as digits as its factorization.

11120000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 11120000113 its reverse (31100002111), we get a palindrome (42220002224).

The spelling of 11120000113 in words is "eleven billion, one hundred twenty million, one hundred thirteen", and thus it is an aban number.