Base | Representation |
---|---|
bin | 110011110010000001… |
… | …0110101100101011111 |
3 | 101122000201122222012001 |
4 | 1213210002311211133 |
5 | 3310214213201143 |
6 | 123030140423131 |
7 | 11014433343613 |
oct | 1474402654537 |
9 | 348021588161 |
10 | 111200131423 |
11 | 43183636667 |
12 | 19674847aa7 |
13 | a642039144 |
14 | 554c749343 |
15 | 2d5c65c14d |
hex | 19e40b595f |
111200131423 has 2 divisors, whose sum is σ = 111200131424. Its totient is φ = 111200131422.
The previous prime is 111200131391. The next prime is 111200131447. The reversal of 111200131423 is 324131002111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111200131423 - 25 = 111200131391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111200131423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111230131423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55600065711 + 55600065712.
It is an arithmetic number, because the mean of its divisors is an integer number (55600065712).
Almost surely, 2111200131423 is an apocalyptic number.
111200131423 is a deficient number, since it is larger than the sum of its proper divisors (1).
111200131423 is an equidigital number, since it uses as much as digits as its factorization.
111200131423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 111200131423 its reverse (324131002111), we get a palindrome (435331133534).
The spelling of 111200131423 in words is "one hundred eleven billion, two hundred million, one hundred thirty-one thousand, four hundred twenty-three".
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