Base | Representation |
---|---|
bin | 10100101101100111… |
… | …11011100110001011 |
3 | 1001200222111011020002 |
4 | 22112303323212023 |
5 | 140233223133233 |
6 | 5035234553215 |
7 | 542365356242 |
oct | 122663734613 |
9 | 31628434202 |
10 | 11120130443 |
11 | 4797029654 |
12 | 21a413880b |
13 | 1082a98a56 |
14 | 776c21959 |
15 | 4513bd6e8 |
hex | 296cfb98b |
11120130443 has 4 divisors (see below), whose sum is σ = 11127600120. Its totient is φ = 11112660768.
The previous prime is 11120130431. The next prime is 11120130467. The reversal of 11120130443 is 34403102111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34403102111 = 7 ⋅4914728873.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11120130443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11120130403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3732605 + ... + 3735582.
It is an arithmetic number, because the mean of its divisors is an integer number (2781900030).
Almost surely, 211120130443 is an apocalyptic number.
11120130443 is a deficient number, since it is larger than the sum of its proper divisors (7469677).
11120130443 is an equidigital number, since it uses as much as digits as its factorization.
11120130443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7469676.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 11120130443 its reverse (34403102111), we get a palindrome (45523232554).
The spelling of 11120130443 in words is "eleven billion, one hundred twenty million, one hundred thirty thousand, four hundred forty-three".
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