Base | Representation |
---|---|
bin | 10000001011101001001… |
… | …110011101010000100011 |
3 | 10221022022012100201220200 |
4 | 100023221032131100203 |
5 | 121204401144143210 |
6 | 2210504040440243 |
7 | 143224516545531 |
oct | 20135116352043 |
9 | 3838265321820 |
10 | 1112014443555 |
11 | 39966a188294 |
12 | 15b623479083 |
13 | 80b29c29082 |
14 | 3bb70da5151 |
15 | 1ddd56260c0 |
hex | 102e939d423 |
1112014443555 has 12 divisors (see below), whose sum is σ = 1927491702240. Its totient is φ = 593074369872.
The previous prime is 1112014443523. The next prime is 1112014443599. The reversal of 1112014443555 is 5553444102111.
1112014443555 is a `hidden beast` number, since 1 + 1 + 1 + 20 + 1 + 44 + 43 + 555 = 666.
It is not a de Polignac number, because 1112014443555 - 25 = 1112014443523 is a prime.
It is a super-2 number, since 2×11120144435552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12355715995 + ... + 12355716084.
It is an arithmetic number, because the mean of its divisors is an integer number (160624308520).
Almost surely, 21112014443555 is an apocalyptic number.
1112014443555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1112014443555 is a deficient number, since it is larger than the sum of its proper divisors (815477258685).
1112014443555 is a wasteful number, since it uses less digits than its factorization.
1112014443555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24711432090 (or 24711432087 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 36.
Adding to 1112014443555 its reverse (5553444102111), we get a palindrome (6665458545666).
The spelling of 1112014443555 in words is "one trillion, one hundred twelve billion, fourteen million, four hundred forty-three thousand, five hundred fifty-five".
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