11120331113 has 4 divisors (see below), whose sum is σ = 11120542020. Its totient is φ = 11120120208.

The previous prime is 11120331043. The next prime is 11120331121. The reversal of 11120331113 is 31113302111.

11120331113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31113302111 = 85133 ⋅365467.

It can be written as a sum of positive squares in 2 ways, for example, as 7987354384 + 3132976729 = 89372^2 + 55973^2 .

It is a cyclic number.

It is not a de Polignac number, because 11120331113 - 2¹⁶ = 11120265577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11120331091 and 11120331100.

It is not an unprimeable number, because it can be changed into a prime (11120331413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52631 + ... + 158147.

It is an arithmetic number, because the mean of its divisors is an integer number (2780135505).

Almost surely, 2^11120331113 is an apocalyptic number.

It is an amenable number.

11120331113 is a deficient number, since it is larger than the sum of its proper divisors (210907).

11120331113 is a wasteful number, since it uses less digits than its factorization.

11120331113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 210906.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11120331113 its reverse (31113302111), we get a palindrome (42233633224).

The spelling of 11120331113 in words is "eleven billion, one hundred twenty million, three hundred thirty-one thousand, one hundred thirteen".