Base | Representation |
---|---|
bin | 1010000111010010011111… |
… | …1111001110001111111011 |
3 | 1110101002112200212202200221 |
4 | 2201310213333032033323 |
5 | 2424143424322323303 |
6 | 35352340401240511 |
7 | 2225263264501324 |
oct | 241644777161773 |
9 | 43332480782627 |
10 | 11120341214203 |
11 | 35a8123788341 |
12 | 12b7243933137 |
13 | 62884a209600 |
14 | 2a6327d3d44b |
15 | 1443eb5b04bd |
hex | a1d27fce3fb |
11120341214203 has 48 divisors (see below), whose sum is σ = 12707060889600. Its totient is φ = 9700349218560.
The previous prime is 11120341214189. The next prime is 11120341214219. The reversal of 11120341214203 is 30241214302111.
It is not a de Polignac number, because 11120341214203 - 213 = 11120341206011 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11120341214293) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3484906338 + ... + 3484909528.
It is an arithmetic number, because the mean of its divisors is an integer number (264730435200).
Almost surely, 211120341214203 is an apocalyptic number.
11120341214203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11120341214203 is a deficient number, since it is larger than the sum of its proper divisors (1586719675397).
11120341214203 is a wasteful number, since it uses less digits than its factorization.
11120341214203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5612 (or 5599 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 11120341214203 its reverse (30241214302111), we get a palindrome (41361555516314).
The spelling of 11120341214203 in words is "eleven trillion, one hundred twenty billion, three hundred forty-one million, two hundred fourteen thousand, two hundred three".
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