111204331041 has 4 divisors (see below), whose sum is σ = 148272441392. Its totient is φ = 74136220692.

The previous prime is 111204331009. The next prime is 111204331099. The reversal of 111204331041 is 140133402111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 111204331041 - 2⁵ = 111204331009 is a prime.

It is a super-3 number, since 3×111204331041³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111204330999 and 111204331017.

It is not an unprimeable number, because it can be changed into a prime (111204331001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18534055171 + ... + 18534055176.

It is an arithmetic number, because the mean of its divisors is an integer number (37068110348).

Almost surely, 2^111204331041 is an apocalyptic number.

It is an amenable number.

111204331041 is a deficient number, since it is larger than the sum of its proper divisors (37068110351).

111204331041 is an equidigital number, since it uses as much as digits as its factorization.

111204331041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37068110350.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 111204331041 its reverse (140133402111), we get a palindrome (251337733152).

The spelling of 111204331041 in words is "one hundred eleven billion, two hundred four million, three hundred thirty-one thousand, forty-one".